Oct 21, 2011 · Writing a simple regex, but I've never been very good at this. What I'm trying to do is check a string (filename) to make sure it only contains a-z, A-Z, 0-9 or the special characters …

[some text] [some number] [some more text] I want to extract the text in [some number] using the Java regex classes. I know roughly what regular expression I want to use (though all suggestions are …

Dec 8, 2018 · The regex compiles fine, and there are already JUnit tests that show how it works. It's just that I'm a bit confused about why the first question mark and colon are there.

When you write a regex in the form of a Java String literal, you can use "\n" to pass the regex compiler a linefeed symbol, or "\\n" to pass it the escape sequence for a linefeed.

@Lupos \s is regex for “whitespace”. To code a literal backslash in Java, you must escape the backslash with another backslash, so to code \s in the regex, you must code "\\s" in your program.

Java - Filtering List Entries by Regex Asked 11 years, 6 months ago Modified 6 years, 11 months ago Viewed 56k times

Nov 26, 2009 · 12 Java's regular expressions don't require you to put a forward-slash (/) or any other delimiter around the regex, as opposed to other languages like Perl, for example.

I'm just wondering if there is a way (maybe with regex) to validate that an input on a Java desktop app is exactly a string formatted as: "YYYY-MM-DD".

Jan 15, 2014 · It takes your normal regular expression and outputs the Java-compatible string expression. Saved me tons of time converting huge regex strings myself. Note that not all regex …

Nov 29, 2010 · Java’s Regex Unicode Problems The problem with Java regexes is that the Perl 1.0 charclass escapes — meaning \w, \b, \s, \d and their complements — are not in Java extended to …